This is a Mooshak version of a CSES problem.
Your task is to calculate the number of trailing zeros in the factorial \(n!\).
For example, \(20!=2432902008176640000\) and it has 4 trailing zeros.
The only input line has an integer \(n\).
Print a line with one integer: the number of trailing zeros in \(n!\).
Example Input | Example Output |
20 |
4 |